2(6x2^+5x)=12

Solution for 2(6x2^+5x)=12 equation:

2(6x^2^+5x)=12

We move all terms to the left:

2(6x^2^+5x)-(12)=0

We multiply parentheses

12x^2+10x-12=0

a = 12; b = 10; c = -12;
Δ = b2-4ac
Δ = 102-4·12·(-12)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-26}{2*12}=\frac{-36}{24}
=-1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+26}{2*12}=\frac{16}{24}
=2/3
$